Question

Question was provided via image upload.

Explanation:

Step1: Balance reaction 7: Match atoms

Count N and O on product side: 2 N, 4 O.
For reactants: $2\text{NO} + \text{O}_2$ gives 2 N, $2+2=4$ O, matching product $2\text{NO}_2$.

Step2: Balance reaction 8: Balance Br first

$\text{AlBr}_3$ has 3 Br, so $\text{KBr}$ needs coefficient 3: $\text{AlBr}_3 + \text{K}
ightarrow 3\text{KBr} + \text{Al}$

Step3: Balance reaction 8: Balance K

3 K on product, so K reactant gets 3: $1\text{AlBr}_3 + 3\text{K}
ightarrow 3\text{KBr} + 1\text{Al}$

Step4: Balance reaction 9: Balance F first

$\text{PdF}_2$ has 2 F, $\text{FeF}_2$ has 2 F, so set $\text{FeO}$ and $\text{PdF}_2$ to 1: $\text{FeO} + \text{PdF}_2
ightarrow \text{FeF}_2 + \text{PdO}$

Step5: Verify reaction 9: Check all atoms

1 Fe, 1 O, 1 Pd, 2 F on both sides.

Answer:

1. $\boldsymbol{2NO + O_2}$
2. $1\text{AlBr}_3 + 3\text{K}

ightarrow 3\text{KBr} + 1\text{Al}$

1. $1\text{FeO}+1\text{PdF}_2

ightarrow 1\text{FeF}_2+1\text{PdO}$