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identify the missing information for each atom or ion. note that the at…

Question

identify the missing information for each atom or ion. note that the atoms and ions are not necessarily neutral.

a se ion has a mass number of 77 and a charge of −2. determine the number of neutrons, protons, and electrons in this ion.

number of neutrons:

number of protons:

number of electrons:

an ion has a mass number of 65, 36 neutrons, and a charge of +1. identify the element symbol, and determine the number of protons and electrons in this ion.

element symbol:

number of protons:

number of electrons:

an atom or ion has 42 neutrons, 36 protons, and 36 electrons. identify the element symbol, and determine the mass number and charge for this atom or ion.

element symbol:

mass number:

charge:

Explanation:

Response
First Part: Se ion

Step1: Find protons (Se atomic number)

Se has atomic number 34, so protons = 34.

Step2: Calculate neutrons (mass - protons)

Mass number = 77, so neutrons = \( 77 - 34 = 43 \).

Step3: Determine electrons (protons + charge magnitude, since charge = -2)

Electrons = \( 34 + 2 = 36 \).

Second Part: Ion with mass 65, neutrons 36, charge +1

Step1: Find protons (mass - neutrons)

Protons = \( 65 - 36 = 29 \) (element is Cu, atomic number 29).

Step2: Determine electrons (protons - charge, since charge = +1)

Electrons = \( 29 - 1 = 28 \).

Third Part: Atom/ion with 42 neutrons, 36 protons, 36 electrons

Step1: Identify element (protons = 36, element is Kr).

Step2: Calculate mass number (protons + neutrons)

Mass number = \( 36 + 42 = 78 \).

Step3: Determine charge (protons - electrons = \( 36 - 36 = 0 \)).

Answer:

s:

First Part:

number of neutrons: \( \boldsymbol{43} \)
number of protons: \( \boldsymbol{34} \)
number of electrons: \( \boldsymbol{36} \)

Second Part:

element symbol: \( \boldsymbol{Cu} \)
number of protons: \( \boldsymbol{29} \)
number of electrons: \( \boldsymbol{28} \)

Third Part:

element symbol: \( \boldsymbol{Kr} \)
mass number: \( \boldsymbol{78} \)
charge: \( \boldsymbol{0} \)