Question

an ionic compound is formed between
d. a non - metallic cation and a metallic anion
b. a metallic cation and a non - metallic anion
a. a non - metal and a non - metal
c. a metalloid and a non - metal
question 2
which of the following best describe the formula for the following compounds lithium nitrate, lithium nitrite
b. lino₃, lino₂
c. li₃n, lino₂
e. li₃n, lino₃
a. lino₂, lino₃
d. lino₃, lin₃
question 3
while naming ionic compounds, roman numerals are used
b. to show the number of non - metal atoms present
a. to show the charge of the metal cation
d. only in binary ionic compounds
c. to show the number of metal atoms present
question 4
if the compound formed by radium and bromine has the formula rabr₂, what is the formula of the compound formed by strontium (sr) and iodine (i)?

Explanation:

• Question 1: Ionic compounds are formed by the transfer of electrons from a metal (which forms a cation) to a non - metal (which forms an anion). So, a metallic cation and a non - metallic anion form an ionic compound.
• Question 2: The formula for lithium nitrate is $LiNO_3$ and for lithium nitrite is $LiNO_2$. Nitrate has the polyatomic ion $NO_3^-$ and nitrite has $NO_2^-$.
• Question 3: Roman numerals are used in naming ionic compounds to show the charge of the metal cation, especially when the metal can have multiple oxidation states.
• Question 4: Radium (Ra) and strontium (Sr) are in the same group (Group 2, alkaline earth metals) and have a + 2 charge. Bromine (Br) and iodine (I) are in Group 17 and have a - 1 charge. So, the formula of the compound formed by Sr and I is $SrI_2$.

Answer:

• Question 1: b. a metallic cation and a non - metallic anion
• Question 2: b. $LiNO_3$, $LiNO_2$
• Question 3: a. to show the charge of the metal cation
• Question 4: $SrI_2$