Question

iron(iii) hydroxide
express your answer as a chemical formula.
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part f

calcium phosphate
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Explanation:

Iron(III) Hydroxide

Step1: Identify ions and charges

Iron(III) has a charge of \( +3 \) (\( \text{Fe}^{3+} \)), hydroxide ion is \( \text{OH}^- \) (charge \( -1 \)).

Step2: Balance charges

To balance, we need 3 \( \text{OH}^- \) for 1 \( \text{Fe}^{3+} \) (since \( 3\times(-1) + 3 = 0 \)).
So the formula is \( \text{Fe(OH)}_3 \).

Calcium Phosphate

Step1: Identify ions and charges

Calcium ion is \( \text{Ca}^{2+} \), phosphate ion is \( \text{PO}_4^{3-} \).

Step2: Balance charges

Find the least common multiple of 2 and 3, which is 6. So we need 3 \( \text{Ca}^{2+} \) (total \( +6 \)) and 2 \( \text{PO}_4^{3-} \) (total \( -6 \)).
The formula is \( \text{Ca}_3(\text{PO}_4)_2 \).

Answer:

s:
Iron(III) hydroxide: \( \text{Fe(OH)}_3 \)
Calcium phosphate: \( \text{Ca}_3(\text{PO}_4)_2 \)