Question

lohse chem 181

1. express the following d

and appropriate units.
$d = \frac{22.251\\ \text{g}}{10.05\\ \text{ml}} = ?$

Explanation:

Step1: Perform division for density

$d = \frac{22.251\ \text{g}}{10.05\ \text{mL}}$

Step2: Calculate the numerical value

$d = 2.214\ \text{g/mL}$

Answer:

$2.214\ \text{g/mL}$