Question

the measured mass and volume of three metal samples are shown. rank the samples according to their density.
sample a: mass 50.0 g, volume 7.9 ml
sample b: mass 50.0 g, volume 6.6 ml
sample c: mass 50.0 g, volume 9.2 ml

1. least dense
2. sample c
3. sample a

Explanation:

Step1: Recall density formula

Density $
ho=\frac{m}{V}$, where $m$ is mass and $V$ is volume.

Step2: Calculate density of Sample A

Given $m = 50.0\ g$ and $V=7.9\ mL$, $
ho_A=\frac{50.0}{7.9}\ g/mL\approx6.33\ g/mL$.

Step3: Calculate density of Sample B

Given $m = 50.0\ g$ and $V = 6.6\ mL$, $
ho_B=\frac{50.0}{6.6}\ g/mL\approx7.58\ g/mL$.

Step4: Calculate density of Sample C

Given $m = 50.0\ g$ and $V=9.2\ mL$, $
ho_C=\frac{50.0}{9.2}\ g/mL\approx5.43\ g/mL$.

Step5: Compare densities

Since $5.43\ g/mL<6.33\ g/mL<7.58\ g/mL$, the order from least - dense to most - dense is Sample C, Sample A, Sample B.

Answer:

Sample C, Sample A, Sample B