Question

module 5 quiz 2 question 13 of 13 (1 point) | question attempt: 1 of 1 classify the following third period fluorides as covalent or ionic. (for this problem, use 2.0 as the cut - off electronegativity difference.) fluoride type of compound naf ionic covalent sf6 ionic covalent

Explanation:

Step1: Recall electronegativity values

Electronegativity of Na is 0.93, F is 3.98, S is 2.58.

Step2: Calculate electronegativity difference for NaF

$\Delta\chi = 3.98 - 0.93=3.05$. Since $3.05>2.0$, NaF is ionic.

Step3: Calculate electronegativity difference for SF₆

$\Delta\chi = 3.98 - 2.58 = 1.4$. Since $1.4<2.0$, SF₆ is covalent.

Answer:

NaF: ionic
SF₆: covalent