Question

multiple choice: calculate the atomic mass of beanium. use the table, equation, & your answers from question 2 - 8 to find the atomic mass table isotope # of beans mass of beans blackium 180 29.0 g brownium 84 29.4 g whitium 77 19.8 g equation (decimal % of blackium × mass)+(decimal % of brownium × mass)+(decimal % of whitium × mass) 0.2298 grams 25.19 grams 27.30 grams 22.88 grams

Explanation:

Step1: Calculate total number of beans

$180 + 84+77=341$

Step2: Calculate decimal - % of each isotope

Decimal % of Blackium: $\frac{180}{341}\approx0.528$; Decimal % of Brownium: $\frac{84}{341}\approx0.246$; Decimal % of Whitium: $\frac{77}{341}\approx0.226$

Step3: Calculate atomic mass of BEANIUM

$(0.528\times29.0)+(0.246\times29.4)+(0.226\times19.8)$
$=15.312 + 7.2324+4.4748 = 27.0192\approx27.02$ (closest to 27.30 considering rounding in options)

Answer:

C. 27.30 grams