Question

name: types of chemical reaction and counting atoms
for each of the chemical reactions below, first identify the reaction type. the types of reactions are synthesis/combination, decomposition, single replacement, double replacement, combustion, and neutralization. then count the number of atoms for the reactants (left side of the arrow) and count the number of atoms for the products (right side of the arrow).
a) o₃ → o + o₂
reaction type:
atoms of reactants atoms of products
o = 3 o = 1+2 = 3
b) hcl + koh → h₂o + kcl
reaction type:
atoms of reactants atoms of products
h = 1+1 = 2 h = 2
cl = cl =
k = k =
o = o =
c) mgcl₂ + li₂co₃ → mgco₃ + 2licl
reaction type:
atoms of reactants atoms of products
mg 1 1
cl 2 2
li 2 2
c 1 1
o 3 3
d) c₆h₁₂ + 9o₂ → 6co₂ + 6h₂o
reaction type:
atoms of reactants atoms of products
c c
h h
o o
e) pb + feso₄ → pbso₄ + fe
reaction type:
atoms of reactants atoms of products
pb pb
fe fe
s s
o o
f) caco₃ → cao + co₂
reaction type:
atoms of reactants atoms of products
ca
c
o
g) p₄ + 3o₂ → 2p₂o₃
reaction type:
atoms of reactants atoms of products
p
o

Explanation:

Step1: Identify reaction type for b)

This is a neutralization reaction as an acid (HCl) and a base (KOH) react to form a salt (KCl) and water.

Step2: Count atoms of reactants for b)

$H = 1 + 1=2$, $Cl = 1$, $K = 1$, $O = 1$

Step3: Count atoms of products for b)

$H = 2$, $Cl = 1$, $K = 1$, $O = 1$

Step4: Identify reaction type for d)

This is a combustion reaction as a hydrocarbon ($C_6H_{12}$) reacts with oxygen ($O_2$) to produce carbon - dioxide ($CO_2$) and water ($H_2O$).

Step5: Count atoms of reactants for d)

$C = 6$, $H = 12$, $O=9\times2 = 18$

Step6: Count atoms of products for d)

$C = 6$, $H = 6\times2=12$, $O=(6\times2)+(6\times1)=18$

Step7: Identify reaction type for e)

This is a single - replacement reaction as one element (Pb) replaces another element (Fe) in a compound ($FeSO_4$).

Step8: Count atoms of reactants for e)

$Pb = 1$, $Fe = 1$, $S = 1$, $O = 4$

Step9: Count atoms of products for e)

$Pb = 1$, $Fe = 1$, $S = 1$, $O = 4$

Step10: Identify reaction type for f)

This is a decomposition reaction as a single compound ($CaCO_3$) breaks down into two simpler compounds ($CaO$ and $CO_2$).

Step11: Count atoms of reactants for f)

$Ca = 1$, $C = 1$, $O = 3$

Step12: Count atoms of products for f)

$Ca = 1$, $C = 1$, $O = 1 + 2=3$

Step13: Identify reaction type for g)

This is a synthesis/combination reaction as two elements ($P_4$ and $O_2$) combine to form a single compound ($2P_2O_3$).

Step14: Count atoms of reactants for g)

$P = 4$, $O = 3\times2 = 6$

Step15: Count atoms of products for g)

$P = 2\times2 = 4$, $O = 2\times3=6$

Answer:

b) Reaction Type: Neutralization
Atoms of Reactants: $H = 2$, $Cl = 1$, $K = 1$, $O = 1$
Atoms of Products: $H = 2$, $Cl = 1$, $K = 1$, $O = 1$
d) Reaction Type: Combustion
Atoms of Reactants: $C = 6$, $H = 12$, $O = 18$
Atoms of Products: $C = 6$, $H = 12$, $O = 18$
e) Reaction Type: Single Replacement
Atoms of Reactants: $Pb = 1$, $Fe = 1$, $S = 1$, $O = 4$
Atoms of Products: $Pb = 1$, $Fe = 1$, $S = 1$, $O = 4$
f) Reaction Type: Decomposition
Atoms of Reactants: $Ca = 1$, $C = 1$, $O = 3$
Atoms of Products: $Ca = 1$, $C = 1$, $O = 3$
g) Reaction Type: Synthesis/Combination
Atoms of Reactants: $P = 4$, $O = 6$
Atoms of Products: $P = 4$, $O = 6$