naming ionic compounds: provide the correct name for the following chemical formulas.
1. mgbr₂
2. cr₂s₃
3. ca(no₃)₂
4. fecl₃
5. k₂o
6. agno₃
7. li₂so₄·10h₂o
8. pbcl₂
9. al₂(co₃)₃
10. cocl₂·6h₂o

Question

Accepted Answer

### 1. $\boldsymbol{MgBr_2}$
# Explanation:
## Step1: Identify cation and anion
Cation: $	ext{Mg}^{2+}$ (magnesium ion), Anion: $	ext{Br}^-$ (bromide ion).

## Step2: Name using ion names
Combine cation name and anion name (change “ide” for bromine).

# Answer: Magnesium bromide

### 2. $\boldsymbol{Cr_2S_3}$
# Explanation:
## Step1: Determine ion charges
Sulfide ($	ext{S}^{2-}$), so $2	ext{Cr}^{x+} + 3	ext{S}^{2-} = 0 \implies x = 3$ (chromium(III) ion).

## Step2: Name with charge (transition metal)
Cation: Chromium(III), Anion: Sulfide.

# Answer: Chromium(III) sulfide

### 3. $\boldsymbol{Ca(NO_3)_2}$
# Explanation:
## Step1: Identify ions
Cation: $	ext{Ca}^{2+}$ (calcium ion), Anion: $	ext{NO}_3^-$ (nitrate ion).

## Step2: Name using polyatomic ion
Combine “calcium” and “nitrate” (subscript 2 balances charge).

# Answer: Calcium nitrate

### 4. $\boldsymbol{FeCl_3}$
# Explanation:
## Step1: Find ion charges
Chloride ($	ext{Cl}^-$), so $	ext{Fe}^{x+} + 3	ext{Cl}^- = 0 \implies x = 3$ (iron(III) ion).

## Step2: Name transition metal with charge
Cation: Iron(III), Anion: Chloride.

# Answer: Iron(III) chloride

### 5. $\boldsymbol{K_2O}$
# Explanation:
## Step1: Identify ions
Cation: $	ext{K}^+$ (potassium ion), Anion: $	ext{O}^{2-}$ (oxide ion).

## Step2: Name using ion names
Combine “potassium” and “oxide” (subscript 2 balances charge).

# Answer: Potassium oxide

### 6. $\boldsymbol{AgNO_3}$
# Explanation:
## Step1: Identify ions
Cation: $	ext{Ag}^+$ (silver ion, fixed charge +1), Anion: $	ext{NO}_3^-$ (nitrate ion).

## Step2: Name with polyatomic ion
Combine “silver” and “nitrate” (charge balances as $1+ + 1- = 0$).

# Answer: Silver nitrate

### 7. $\boldsymbol{Li_2SO_4 \cdot 10H_2O}$
# Explanation:
## Step1: Identify ions and hydrate
Cation: $	ext{Li}^+$ (lithium ion), Anion: $	ext{SO}_4^{2-}$ (sulfate ion); Hydrate: $10	ext{H}_2	ext{O}$ (deca-).

## Step2: Name salt and hydrate
Lithium sulfate + decahydrate.

# Answer: Lithium sulfate decahydrate

### 8. $\boldsymbol{PbCl_2}$
# Explanation:
## Step1: Determine ion charges
Chloride ($	ext{Cl}^-$), so $	ext{Pb}^{x+} + 2	ext{Cl}^- = 0 \implies x = 2$ (lead(II) ion, since Pb has multiple charges).

## Step2: Name transition metal with charge
Cation: Lead(II), Anion: Chloride.

# Answer: Lead(II) chloride

### 9. $\boldsymbol{Al_2(CO_3)_3}$
# Explanation:
## Step1: Identify ions
Cation: $	ext{Al}^{3+}$ (aluminum ion, fixed charge +3), Anion: $	ext{CO}_3^{2-}$ (carbonate ion).

## Step2: Name with polyatomic ion
Combine “aluminum” and “carbonate” (subscripts balance $2(3+) + 3(2-) = 0$).

# Answer: Aluminum carbonate

### 10. $\boldsymbol{CoCl_2 \cdot 6H_2O}$
# Explanation:
## Step1: Identify ions and hydrate
Cation: $	ext{Co}^{2+}$ (cobalt(II) ion, since $2	ext{Cl}^-$), Anion: $	ext{Cl}^-$ (chloride); Hydrate: $6	ext{H}_2	ext{O}$ (hexa-).

## Step2: Name salt and hydrate
Cobalt(II) chloride + hexahydrate.

# Answer: Cobalt(II) chloride hexahydrate

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QUESTION IMAGE

Question

Explanation:

1. $\boldsymbol{MgBr_2}$

Step1: Identify cation and anion

Step2: Name using ion names

Step1: Determine ion charges

Step2: Name with charge (transition metal)

Step1: Identify ions

Step2: Name using polyatomic ion

Answer:

2. $\boldsymbol{Cr_2S_3}$