Question

naming warm - ups (10/3 - 10/10)
day 1 (10/3)

1. write the name for p₅n₃.
2. write the chemical formula for zinc chlorate.
3. write the chemical formula for dihydrogen hexabromide.

day 2 (10/6)

1. write the chemical formula for heptanitrogen pentafluoride.
2. write the name for srbr₂.
3. write the name for pd(so₄)₂.

Explanation:

Step1: Name $P_{5}N_{3}$

This is a binary molecular compound. The prefix for 5 is "penta -" and for 3 is "tri -". The first element is phosphorus and the second is nitrogen. So the name is pentaphosphorus trinitride.

Step2: Chemical formula for zinc chlorate

Zinc has a +2 charge ($Zn^{2 + }$) and chlorate is $ClO_{3}^{-}$. To balance the charges, we need 2 chlorate ions for 1 zinc ion. The formula is $Zn(ClO_{3})_{2}$.

Step3: Chemical formula for dihydrogen hexabromide

"Dihydrogen" means 2 hydrogen atoms ($H$) and "hexabromide" means 6 bromine atoms ($Br$). The formula is $H_{2}Br_{6}$.

Step4: Chemical formula for heptanitrogen pentafluoride

"Heptanitrogen" means 7 nitrogen atoms ($N$) and "pentafluoride" means 5 fluorine atoms ($F$). The formula is $N_{7}F_{5}$.

Step5: Name $SrBr_{2}$

This is an ionic compound. The metal is strontium ($Sr$) and the non - metal is bromine. In ionic compounds, the non - metal's ending is changed to "-ide". The name is strontium bromide.

Step6: Name $Pd(SO_{4})_{2}$

The metal is palladium ($Pd$). The polyatomic ion is sulfate ($SO_{4}^{2 - }$). Since there are 2 sulfate ions with a total charge of - 4, the charge on palladium is + 4. The name is palladium(IV) sulfate.

Answer:

1. Pentaphosphorus trinitride
2. $Zn(ClO_{3})_{2}$
3. $H_{2}Br_{6}$
4. $N_{7}F_{5}$
5. Strontium bromide
6. Palladium(IV) sulfate