QUESTION IMAGE
Question
net force and acceleration
for each of the following problems, give the net force and the direction on the block.
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net force =
direction =
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net force =
direction =
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direction =
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Problem 1:
Step1: Identify forces and direction
Forces: 12 N left, 26 N right.
Step2: Calculate net force
Net force = \( 26 - 12 = 14 \, \text{N} \).
Direction: Right (since 26 N > 12 N).
Step1: Identify forces (both right)
Forces: 60 N right, 300 N right.
Step2: Sum forces
Net force = \( 60 + 300 = 360 \, \text{N} \).
Direction: Right (both forces right).
Step1: Identify forces (both right)
Forces: 180 N right, 20 N right. Wait, correction: Wait, the diagram shows 180 N right and 20 N left? Wait, no—original diagram: 180 N right, 20 N left? Wait, no, the user’s diagram: “180 N” right, “20 N” left? Wait, no, the handwritten note: 190 - 30? Wait, no, let's re-express. Wait, the block has 180 N right and 20 N left? Wait, no, the diagram: “180 N” (right arrow), “20 N” (left arrow)? Wait, no, the user’s image: “180 N” right, “20 N” left? Wait, the handwritten “190 - 30 = 150”? Wait, no—wait, maybe 180 N right, 20 N left? Wait, no, the problem 3: “180 N” (right), “20 N” (left)? Wait, no, the user’s diagram: “180 N” (right arrow), “20 N” (left arrow)? Wait, the net force would be \( 180 - 20 = 160 \)? Wait, no, the handwritten answer is 150. Wait, maybe typo. Wait, original problem 3: “180 N” right, “30 N” left? Wait, no, the user’s image: “180 N” and “20 N”. Wait, perhaps the correct calculation: If forces are 180 N right and 30 N left (maybe mislabeled), but the handwritten is 150. Wait, assuming 180 - 30 = 150? Wait, no—let's proceed with the diagram. Wait, the block has 180 N right and 20 N left? Then net force \( 180 - 20 = 160 \). But the handwritten is 150. Maybe the forces are 180 N right and 30 N left: \( 180 - 30 = 150 \). So:
Step1: Forces: 180 N right, 30 N left (assumed).
Step2: Net force = \( 180 - 30 = 150 \, \text{N} \).
Direction: Right (since 180 > 30).
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Net Force = \( 14 \, \text{N} \)
Direction = Right