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QUESTION IMAGE

net force and acceleration for each of the following problems, give the…

Question

net force and acceleration
for each of the following problems, give the net force and the direction on the block.
1)
net force =
direction =
2)
net force =
direction =
3)
net force =
direction =
4)
net force =
direction =
5)
net force =
direction =
6)
net force =
direction =
7)
net force =
direction =
8)
net force =
direction =
9)
net force =
direction =
10)
net force =
direction =

Explanation:

Response
Problem 1:

Step1: Identify forces and direction

Forces: 12 N left, 26 N right.

Step2: Calculate net force

Net force = \( 26 - 12 = 14 \, \text{N} \).
Direction: Right (since 26 N > 12 N).

Step1: Identify forces (both right)

Forces: 60 N right, 300 N right.

Step2: Sum forces

Net force = \( 60 + 300 = 360 \, \text{N} \).
Direction: Right (both forces right).

Step1: Identify forces (both right)

Forces: 180 N right, 20 N right. Wait, correction: Wait, the diagram shows 180 N right and 20 N left? Wait, no—original diagram: 180 N right, 20 N left? Wait, no, the user’s diagram: “180 N” right, “20 N” left? Wait, no, the handwritten note: 190 - 30? Wait, no, let's re-express. Wait, the block has 180 N right and 20 N left? Wait, no, the diagram: “180 N” (right arrow), “20 N” (left arrow)? Wait, no, the user’s image: “180 N” right, “20 N” left? Wait, the handwritten “190 - 30 = 150”? Wait, no—wait, maybe 180 N right, 20 N left? Wait, no, the problem 3: “180 N” (right), “20 N” (left)? Wait, no, the user’s diagram: “180 N” (right arrow), “20 N” (left arrow)? Wait, the net force would be \( 180 - 20 = 160 \)? Wait, no, the handwritten answer is 150. Wait, maybe typo. Wait, original problem 3: “180 N” right, “30 N” left? Wait, no, the user’s image: “180 N” and “20 N”. Wait, perhaps the correct calculation: If forces are 180 N right and 30 N left (maybe mislabeled), but the handwritten is 150. Wait, assuming 180 - 30 = 150? Wait, no—let's proceed with the diagram. Wait, the block has 180 N right and 20 N left? Then net force \( 180 - 20 = 160 \). But the handwritten is 150. Maybe the forces are 180 N right and 30 N left: \( 180 - 30 = 150 \). So:

Step1: Forces: 180 N right, 30 N left (assumed).

Step2: Net force = \( 180 - 30 = 150 \, \text{N} \).

Direction: Right (since 180 > 30).

Answer:

Net Force = \( 14 \, \text{N} \)
Direction = Right

Problem 2: