Question

1. to neutralize 0.035 moles of baking soda, one needs ______ mole(s) of acetic acid. (1 point)
2. a student was performing a reaction of neutralization of baking soda with vinegar (the same

Explanation:

Step1: Write the neutralization reaction

The reaction between baking - soda ($NaHCO_3$) and acetic acid ($CH_3COOH$) is $NaHCO_3+CH_3COOH = CH_3COONa + H_2O+CO_2$.

Step2: Determine the mole - ratio

From the balanced chemical equation, the mole - ratio of $NaHCO_3$ to $CH_3COOH$ is 1:1.

Step3: Calculate the moles of acetic acid

If we have 0.035 moles of $NaHCO_3$, and the mole - ratio of $NaHCO_3$ to $CH_3COOH$ is 1:1, then the moles of $CH_3COOH$ needed for neutralization is also 0.035 moles.

Answer:

0.035