Question

1. an object placed in a graduated cylinder raises the volume from 12.2 ml to 14.5 ml. find the volume of the object.

Explanation:

Step1: Identify the initial and final volumes

The initial volume of liquid in the graduated cylinder is \( V_{initial} = 12.2 \, \text{mL} \) and the final volume after placing the object is \( V_{final} = 14.5 \, \text{mL} \).

Step2: Calculate the volume of the object

The volume of the object (\( V_{object} \)) is the difference between the final volume and the initial volume. So, we use the formula \( V_{object} = V_{final} - V_{initial} \).

Substituting the values, we get \( V_{object} = 14.5 - 12.2 \).

Calculating the subtraction: \( 14.5 - 12.2 = 2.3 \, \text{mL} \). Since \( 1 \, \text{mL} = 1 \, \text{cm}^3 \), the volume of the object is also \( 2.3 \, \text{cm}^3 \).

Answer:

The volume of the object is \( 2.3 \, \text{mL} \) (or \( 2.3 \, \text{cm}^3 \)).