Question

part b
determine how many moles of ba(oh)₂ are required to completely neutralize 0.425 mol of hc₂h₃o₂.
express the number of moles numerically.
n = mol

Explanation:

Step1: Write the balanced chemical equation

The reaction between $Ba(OH)_2$ and $HC_2H_3O_2$ is $Ba(OH)_2 + 2HC_2H_3O_2=Ba(C_2H_3O_2)_2 + 2H_2O$. The mole - ratio of $Ba(OH)_2$ to $HC_2H_3O_2$ is 1:2.

Step2: Calculate the moles of $Ba(OH)_2$

Let $n_{Ba(OH)_2}$ be the moles of $Ba(OH)_2$ and $n_{HC_2H_3O_2}$ be the moles of $HC_2H_3O_2$. From the mole - ratio, $n_{Ba(OH)_2}=\frac{1}{2}n_{HC_2H_3O_2}$. Given $n_{HC_2H_3O_2} = 0.425$ mol, then $n_{Ba(OH)_2}=\frac{1}{2}\times0.425$ mol.
$n_{Ba(OH)_2}= 0.2125$ mol

Answer:

0.2125