Question

part 2 of 2
what is the molarity of glucose in the blood?
$square$ m
$0.135\\% \left(\frac{w}{v}\
ight)$ glucose

Explanation:

Step1: Define % (w/v) meaning

0.135% (w/v) = $\frac{0.135\ \text{g glucose}}{100\ \text{mL solution}}$

Step2: Convert volume to liters

$100\ \text{mL} = 0.1\ \text{L}$

Step3: Calculate glucose molar mass

Glucose formula: $\text{C}_6\text{H}_{12}\text{O}_6$
Molar mass = $6(12.01) + 12(1.008) + 6(16.00) = 180.16\ \text{g/mol}$

Step4: Compute moles of glucose

$\text{Moles} = \frac{0.135\ \text{g}}{180.16\ \text{g/mol}} \approx 7.493 \times 10^{-4}\ \text{mol}$

Step5: Calculate molarity

$\text{Molarity} = \frac{\text{Moles}}{\text{Volume (L)}} = \frac{7.493 \times 10^{-4}\ \text{mol}}{0.1\ \text{L}}$

Answer:

$0.0075$ M (or $7.5 \times 10^{-3}$ M)