Question

this passage describes a chemical reaction. read the passage. then, follow the instructions below.
did you know that glow sticks give off light because of a chemical reaction? a glow stick contains two compounds: hydrogen peroxide (h₂o₂) and diphenyl oxalate (c₁₄h₁₀o₄), which are separated by a barrier inside the glow stick. when you bend a glow stick, the barrier breaks and the substances mix, forming phenol (c₆h₆o) and carbon dioxide (co₂). the energy released by this reaction makes the glow stick give off colored light.
complete the table to classify the substances in this chemical reaction.
table with columns: substance, reactant, product; rows: carbon dioxide (co₂), diphenyl oxalate (c₁₄h₁₀o₄), hydrogen peroxide (h₂o₂), phenol (c₆h₆o)

Explanation:

To solve this, we analyze the passage:

• Reactants are substances that react (mixed when the barrier breaks). The passage says the glow stick has hydrogen peroxide ($\ce{H_2O_2}$) and diphenyl oxalate ($\ce{C_{14}H_{10}O_4}$) separated by a barrier; these are the reactants.
• Products are substances formed from the reaction. The passage states the reaction forms phenol ($\ce{C_6H_6O}$) and carbon dioxide ($\ce{CO_2}$); these are the products.

Step 1: Classify carbon dioxide ($\ce{CO_2}$)

From the passage, $\ce{CO_2}$ is formed (a product). So:

• Reactant: $\boldsymbol{\times}$ (not a reactant)
• Product: $\boldsymbol{\checkmark}$ (is a product)

Step 2: Classify diphenyl oxalate ($\ce{C_{14}H_{10}O_4}$)

From the passage, diphenyl oxalate is a reactant (mixed when the barrier breaks). So:

• Reactant: $\boldsymbol{\checkmark}$ (is a reactant)
• Product: $\boldsymbol{\times}$ (not a product)

Step 3: Classify hydrogen peroxide ($\ce{H_2O_2}$)

From the passage, hydrogen peroxide is a reactant (mixed when the barrier breaks). So:

• Reactant: $\boldsymbol{\checkmark}$ (is a reactant)
• Product: $\boldsymbol{\times}$ (not a product)

Step 4: Classify phenol ($\ce{C_6H_6O}$)

From the passage, phenol is formed (a product). So:

• Reactant: $\boldsymbol{\times}$ (not a reactant)
• Product: $\boldsymbol{\checkmark}$ (is a product)

Final Table (checkmarks for correct classification):

Substance	Reactant	Product
diphenyl oxalate ($\ce{C_{14}H_{10}O_4}$)	$\checkmark$	$\times$
hydrogen peroxide ($\ce{H_2O_2}$)	$\checkmark$	$\times$
phenol ($\ce{C_6H_6O}$)	$\times$	$\checkmark$

(Note: In the original table, you would mark the appropriate boxes with checkmarks or "X" based on this analysis.)

Answer:

To solve this, we analyze the passage:

• Reactants are substances that react (mixed when the barrier breaks). The passage says the glow stick has hydrogen peroxide ($\ce{H_2O_2}$) and diphenyl oxalate ($\ce{C_{14}H_{10}O_4}$) separated by a barrier; these are the reactants.
• Products are substances formed from the reaction. The passage states the reaction forms phenol ($\ce{C_6H_6O}$) and carbon dioxide ($\ce{CO_2}$); these are the products.

Step 1: Classify carbon dioxide ($\ce{CO_2}$)

From the passage, $\ce{CO_2}$ is formed (a product). So:

• Reactant: $\boldsymbol{\times}$ (not a reactant)
• Product: $\boldsymbol{\checkmark}$ (is a product)

Step 2: Classify diphenyl oxalate ($\ce{C_{14}H_{10}O_4}$)

From the passage, diphenyl oxalate is a reactant (mixed when the barrier breaks). So:

• Reactant: $\boldsymbol{\checkmark}$ (is a reactant)
• Product: $\boldsymbol{\times}$ (not a product)

Step 3: Classify hydrogen peroxide ($\ce{H_2O_2}$)

From the passage, hydrogen peroxide is a reactant (mixed when the barrier breaks). So:

• Reactant: $\boldsymbol{\checkmark}$ (is a reactant)
• Product: $\boldsymbol{\times}$ (not a product)

Step 4: Classify phenol ($\ce{C_6H_6O}$)

From the passage, phenol is formed (a product). So:

• Reactant: $\boldsymbol{\times}$ (not a reactant)
• Product: $\boldsymbol{\checkmark}$ (is a product)

Final Table (checkmarks for correct classification):

Substance	Reactant	Product
diphenyl oxalate ($\ce{C_{14}H_{10}O_4}$)	$\checkmark$	$\times$
hydrogen peroxide ($\ce{H_2O_2}$)	$\checkmark$	$\times$
phenol ($\ce{C_6H_6O}$)	$\times$	$\checkmark$

(Note: In the original table, you would mark the appropriate boxes with checkmarks or "X" based on this analysis.)