Question

1. please draw the structure of the products of the following reactions: a. chemical - structure $xrightarrow{h_2o, h_2so_4}$ b. chemical - structure $xrightarrow{h_2, catalyst}$

Explanation:

Step1: Analyze reaction a

This is an acid - catalyzed hydration of an alkene. According to Markovnikov's rule, the hydrogen from water will add to the carbon of the double - bond that has more hydrogens, and the hydroxyl group will add to the more substituted carbon.

Step2: Draw product of reaction a

The product will be an alcohol. The structure will have the hydroxyl group attached to the more substituted carbon of the original double - bond.

Step3: Analyze reaction b

This is a hydrogenation reaction of an alkene. In the presence of a catalyst (such as Pd, Pt, or Ni), hydrogen adds across the double - bond.

Step4: Draw product of reaction b

The product will be an alkane. The double - bond will be converted to a single bond with the addition of two hydrogens (one on each carbon of the original double - bond).

Answer:

a. The product of reaction a is an alcohol with the hydroxyl group on the more substituted carbon of the original double - bond.
b. The product of reaction b is an alkane with the double - bond fully hydrogenated. (It is not possible to draw the actual structures in this text - based format, but the above descriptions should allow for drawing them.)