Question

provide 3 missing symbols and 2 numbers
16 4 d 1
n + a → b + c
e 2 9 0
a = 1
b = 2
c = 3
d = 4
e = 5
a. γ (gamma) b. 0 c. 232 d. 90 e. he f. th g. 4
h. 88 i. 188 j. 114 k. re l. -1 m. e n. bi
o. pb p. 82 q. 208 r. 248 s. sn t. 7 u. f

Explanation:

Step1: Analyze nuclear - like reaction

We assume this is a nuclear - related reaction where we need to balance the mass numbers and atomic numbers. However, without more context about the nature of the reaction, we can only make some general assumptions based on the given options.

Step2: Consider common nuclear particles and numbers

Let's assume this is a simple alpha - decay or a similar nuclear transformation. Alpha particle is represented as $He$ (option E). For numbers, we look at typical values in nuclear reactions.

Answer:

1. E. He
2. A. $\gamma$ (gamma)
3. M. e
4. 88
5. 90