Question

question 10 (1 point) calculate the volume of a gas that has a density of 18.75 g/l and a mass of 225 g. remember to round according to significant digits! 12.0 l 12 l 1.20 l 12.00 l

Explanation:

Step1: Recall density formula

The density formula is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass and $V$ is volume. We need to solve for $V$, so $V = \frac{m}{
ho}$.

Step2: Substitute values

Given $m = 225\ g$ and $
ho=18.75\ g/L$, then $V=\frac{225\ g}{18.75\ g/L}=12\ L$.

Step3: Consider significant - digits

The mass 225 g has 3 significant digits and the density 18.75 g/L has 4 significant digits. When dividing, the result should be reported with the same number of significant digits as the value with the least number of significant digits in the calculation. So the answer is 12 L.

Answer:

12 L