Question

question 5 (10 points) how many atoms are present in 0.850 g of sulfur (s) a 1.60x10^22 b 5.12x10^23 c 8.50x10^20 d 1.29x10^22

Explanation:

Step1: Find moles of sulfur

Molar mass of S = 32.07 g/mol.
$\text{Moles of S} = \frac{0.850\ \text{g}}{32.07\ \text{g/mol}} \approx 0.0265\ \text{mol}$

Step2: Calculate number of atoms

Use Avogadro's number $N_A = 6.022\times10^{23}\ \text{atoms/mol}$.
$\text{Number of atoms} = 0.0265\ \text{mol} \times 6.022\times10^{23}\ \text{atoms/mol} \approx 1.60\times10^{22}$

Answer:

a. $1.60\times10^{22}$