Question

question 11 1 pts place the following substances in order of increasing boiling point. ch3ch2oh ch3och3 ch3ch2ch3 ch3ch2oh < ch3och3 < ch3ch2ch3 ch3och3 < ch3ch2ch3 < ch3ch2oh ch3och3 < ch3ch2oh < ch3ch2ch3 ch3ch2ch3 < ch3och3 < ch3ch2oh question 12 1 pts choose the substance with the lowest boiling point. h2o2 c2h6 nh3 f2 h2s

Explanation:

Step1: Analyze intermolecular forces

Boiling - point is related to the strength of intermolecular forces. $CH_3CH_2CH_3$ is a non - polar molecule with only London dispersion forces. $CH_3OCH_3$ is polar and has dipole - dipole forces in addition to London dispersion forces. $CH_3CH_2OH$ can form hydrogen bonds, which are stronger than dipole - dipole and London dispersion forces.

Step2: Determine boiling - point order

Since hydrogen bonds > dipole - dipole > London dispersion forces, the order of increasing boiling point is $CH_3CH_2CH_3

For question 12:

Step1: Analyze intermolecular forces of each substance

$H_2O_2$ can form hydrogen bonds. $CCl_4$ is non - polar with only London dispersion forces. $NH_3$ can form hydrogen bonds. $F_2$ is non - polar with only London dispersion forces. $H_2S$ is polar with dipole - dipole forces and London dispersion forces.

Step2: Compare the strength of intermolecular forces

Among them, $F_2$ has the weakest intermolecular forces (only London dispersion forces and it has a small molar mass compared to $CCl_4$).

Answer:

Question 11: $CH_3CH_2CH_3Question 12: $F_2$