Question

question 14 (5 points)
what is the molarity of a solution in which 4.00 mol of potassium chloride is dissolved in 3.00 l of solution?

a) 1.33 m

b) 6.00 m

c) 2.67 m

d) 4.00 m

Explanation:

Step1: Recall Molarity Formula

Molarity ($M$) is defined as moles of solute ($n$) divided by volume of solution in liters ($V$), so $M = \frac{n}{V}$.

Step2: Substitute Values

Given $n = 4.00\ \text{mol}$ and $V = 3.00\ \text{L}$, substitute into the formula: $M = \frac{4.00\ \text{mol}}{3.00\ \text{L}}$.

Step3: Calculate Result

$\frac{4.00}{3.00} \approx 1.33\ \text{M}$.

Answer:

a) 1.33 M