Question

question 15
0.5 pts
a molecule has with the formula cₙh₂ₙ₊₂ will have the same dou as a compound with which of the following formulas?
○ cₙh₂ₙ₊₁cl
○ c₂ₙhₙ
○ cₙh₃ₙ₋₂

Explanation:

Step1: Recall DOU formula

The degree - of - unsaturation (DOU) formula for a hydrocarbon with formula $C_xH_y$ is $DOU=\frac{2x + 2-y}{2}$. For a hydrocarbon with formula $C_nH_{2n + 2}$, $DOU=\frac{2n+2-(2n + 2)}{2}=0$, which means it is a saturated hydrocarbon.

Step2: Calculate DOU for $C_nH_{2n+1}Cl$

Chlorine (Cl) is monovalent like hydrogen. So the formula $C_nH_{2n+1}Cl$ is equivalent to $C_nH_{2n + 2}$ in terms of DOU. Using the DOU formula: $DOU=\frac{2n+2-(2n + 2)}{2}=0$.

Step3: Calculate DOU for $C_{2n}H_n$

Using the DOU formula $DOU=\frac{2(2n)+2 - n}{2}=\frac{4n+2 - n}{2}=\frac{3n + 2}{2}
eq0$.

Step4: Calculate DOU for $C_nH_{3n-2}$

Using the DOU formula $DOU=\frac{2n+2-(3n - 2)}{2}=\frac{2n+2-3n + 2}{2}=\frac{4 - n}{2}
eq0$.

Answer:

$C_nH_{2n+1}Cl$