Question

question 17 using the equation 2c6h6 + 15o2 → 12co2+ 22h2o, blank 1 grams of co2 would be produced from 3.6 moles of c6h6. blank 1 add your answer 3 points

Explanation:

Step1: Determine mole - ratio

From the balanced equation \(2C_{12}H_{22}+15O_2
ightarrow12CO_2 + 22H_2O\), the mole - ratio of \(C_{12}H_{22}\) to \(CO_2\) is \(2:12\) or \(1:6\).

Step2: Calculate moles of \(CO_2\)

If we have 9.6 moles of \(C_{12}H_{22}\), using the mole - ratio, the moles of \(CO_2\) produced is \(n(CO_2)=9.6\times6 = 57.6\) moles.

Step3: Calculate mass of \(CO_2\)

The molar mass of \(CO_2\) is \(M(CO_2)=12 + 2\times16=44\) g/mol. The mass of \(CO_2\), \(m = n\times M\), so \(m(CO_2)=57.6\times44 = 2534.4\) g.

Answer:

2534.4