Question

question 18 of 20 what nacl concentration results when 304 ml of a 0.600 m nacl solution is mixed with 467 ml of a 0.260 m nacl solution? concentration: m

Explanation:

Step1: Calculate moles in first solution

Use $n = M\times V$. For the first solution, $V_1=304\ mL = 0.304\ L$ and $M_1 = 0.600\ M$. So $n_1 = 0.600\ M\times0.304\ L= 0.1824\ mol$.

Step2: Calculate moles in second solution

For the second solution, $V_2 = 467\ mL=0.467\ L$ and $M_2 = 0.260\ M$. So $n_2=0.260\ M\times0.467\ L = 0.12142\ mol$.

Step3: Calculate total moles

$n_{total}=n_1 + n_2=0.1824\ mol+ 0.12142\ mol = 0.30382\ mol$.

Step4: Calculate total volume

$V_{total}=V_1 + V_2=304\ mL + 467\ mL=771\ mL = 0.771\ L$.

Step5: Calculate final concentration

Use $M=\frac{n}{V}$. So $M_{final}=\frac{0.30382\ mol}{0.771\ L}\approx0.394\ M$.

Answer:

$0.394$