Question

question 19 (0.5 points) give the formula from the systematic name manganese (vii) selenide 1 2 a. mn2 b. mn c. mn3 d. (cn)2 e. se3 f. (so3)2 g. (c2h3o2)2 h. c2h3o2 i. hso3 j. se7 k. c3 l. po3 m. hpo3 n. h2po3 o. oh p. (oh)2 q. s r. so4 s. (so4)2 t. man3

Explanation:

Step1: Determine ion charges

Manganese (VII) has a charge of +7 ($Mn^{7+}$), and selenide ion has a charge of - 2 ($Se^{2-}$).

Step2: Use charge - balance

To balance the charges in an ionic compound, we need to find the ratio of cations to anions such that the overall charge is zero. Let the formula be $Mn_xSe_y$. Then $7x-2y = 0$. The smallest whole - number values for $x$ and $y$ that satisfy this equation are $x = 2$ and $y = 7$. So the formula is $Mn_2Se_7$. From the given options, the correct parts are B. Mn and J. Se7.

Answer:

B. Mn, J. Se7