Question

question 27 of 30
what is the oxidation state of n in nano₃?
a. -1
b. 0
c. +6
d. +5

Explanation:

Step1: Recall oxidation - state rules

The oxidation state of Na is +1 and of O is -2 in most compounds.

Step2: Set up an equation

Let the oxidation state of N be \(x\). For the neutral compound \(NaNO_3\), the sum of oxidation states is 0. So, \(+ 1+x+3\times(-2)=0\).

Step3: Solve the equation

\[

$$\begin{align*} 1 + x-6&=0\\ x-5&=0\\ x&= + 5 \end{align*}$$

\]

Answer:

D. +5