Question

question 37 of 49
determine the hybridization of the central atom for each molecule.
(image of alcl₄⁻ structure with cl atoms around al and electron dots, and image of s=c=s structure with s atoms having electron dots)
for alcl₄⁻:
○ sp
○ sp²
○ sp³
○ sp³d
○ sp³d²
for s=c=s:
○ sp
○ sp²
○ sp³
○ sp³d
○ sp³d²

Explanation:

Step1: Count electron domains for Al

In $\text{AlCl}_4^-$, the central Al atom is bonded to 4 Cl atoms (4 bonding domains, no lone pairs). Total electron domains = 4.

Step2: Match to hybridization

4 electron domains correspond to $sp^3$ hybridization.

Step3: Count electron domains for C

In $\text{S=C=S}$, the central C atom has 2 double bonds (2 bonding domains, no lone pairs). Total electron domains = 2.

Step4: Match to hybridization

2 electron domains correspond to $sp$ hybridization.

Answer:

For $\text{AlCl}_4^-$: $\boldsymbol{sp^3}$
For $\text{S=C=S}$: $\boldsymbol{sp}$