Question

question 3 (1 point)
what is the correct noble gas notation for gallium (ga)?
blank 1:
question 4 (1 point)
how many electrons does a neutral atom of oxygen have?

Explanation:

Step1: Recall noble - gas notation rules

Noble - gas notation starts with the noble gas that comes before the element in the periodic table and then writes the remaining electron configuration. Gallium (Ga) has an atomic number of 31. The noble gas before Ga is Ar (atomic number 18).

Step2: Determine remaining electrons

Ga has 31 electrons. After accounting for the 18 electrons of Ar, there are 31 - 18=13 remaining electrons. The electron - configuration of these 13 electrons is $4s^{2}3d^{10}4p^{1}$.

Step3: Write noble - gas notation

The noble - gas notation for Ga is $[Ar]4s^{2}3d^{10}4p^{1}$.

Step4: Recall electron number in neutral atom

For a neutral atom, the number of electrons is equal to the atomic number. Oxygen has an atomic number of 8. So a neutral oxygen atom has 8 electrons.

Answer:

Question 3: $[Ar]4s^{2}3d^{10}4p^{1}$
Question 4: 8