Question

question 3 (2 points)
what is the molarity of a solution of 152.7 grams of mgcl2 (mm = 95.21 g/mol) dissolved in water to a total volume of 2.5 l? do not include units in your response.
your answer:
answer

Explanation:

Step1: Calculate moles of MgCl2

$n=\frac{m}{MM}=\frac{152.7}{95.21}$

Step2: Calculate molarity

$M=\frac{n}{V}=\frac{\frac{152.7}{95.21}}{2.5}$
$M=\frac{152.7}{95.21\times2.5}=\frac{152.7}{238.025}\approx0.64$

Answer:

0.64