QUESTION IMAGE
Question
reactant
6co₂ + 6h₂o → c₆h₁₂o₆ + 6o₂
subscript coefficient compound element
use the chemical equation below to answer questions 1-2. label the reactants and products
reactant product
c₂h₅oh + 3o₂ → 2co₂ + 3h₂o
1 what elements are involved in this chemical equation? carbon
oxygen hydrogen
2 how many compounds can be found on the reactants side of the equation?
1
use the chemical equation below to answer questions 9-10. label the reactants and products.
reactant product
nh₃ + hno₃ → nh₄no₃ + h₂
- complete the table below. identify the elements and number of atoms for each element in the table below.
reactants products
element # of atoms # of atoms element
n 2 2 n
h 4 6 h
o 3 3 o
- does the chemical equation follow the law of conservation of mass? explain your answer. no because there is two more hydrogen on the products
use the chemical equation below to determine if the statements below are true. place a checkmark in the space if the statement is correct and place an x if the statement is incorrect. label the reactants and products.
reactant products
zn + h₂so₄ → znso₄ + h₂
correct or incorrect statement
- 4 sulfur atoms are on the reactants side, and 1 sulfur atom is on the products side.
- there are 4 different elements involved in this chemical equation.
- 2 hydrogen atoms are on the reactants side, and 2 hydrogen atoms are on the products side.
- only one new substance is formed on the products side.
Question 1: What elements are involved in the chemical equation $\boldsymbol{\ce{C2H5OH + 3O2 -> 2CO2 + 3H2O}}$?
Step 1: Identify elements in each compound
- In $\ce{C2H5OH}$: Elements are Carbon (C), Hydrogen (H), Oxygen (O).
- In $\ce{O2}$: Element is Oxygen (O).
- In $\ce{CO2}$: Elements are Carbon (C), Oxygen (O).
- In $\ce{H2O}$: Elements are Hydrogen (H), Oxygen (O).
Step 2: Collect unique elements
Combine all elements and remove duplicates. The unique elements are Carbon (C), Hydrogen (H), and Oxygen (O).
Step 1: Define "compound" and "element"
A compound is a substance with two or more different elements. An element (in elemental form) has only one type of atom (e.g., $\ce{O2}$ is an element, $\ce{C2H5OH}$ is a compound).
Step 2: Analyze reactants
Reactants: $\ce{C2H5OH}$ (compound, 3 elements) and $\ce{3O2}$ (element, 1 type of atom). So only $\ce{C2H5OH}$ is a compound on the reactants side.
Step 1: Recall the law
The law of conservation of mass states that the number of atoms of each element must be equal on both sides (reactants and products) in a balanced chemical equation.
Step 2: Compare atom counts
- Nitrogen (N): 2 (reactants) vs. 2 (products) → balanced.
- Oxygen (O): 3 (reactants) vs. 3 (products) → balanced.
- Hydrogen (H): 4 (reactants: 3 from $\ce{NH3}$, 1 from $\ce{HNO3}$) vs. 6 (products: 4 from $\ce{NH4NO3}$, 2 from $\ce{H2}$) → unbalanced (4 ≠ 6).
Since the number of H atoms is not equal, the equation does not follow the law of conservation of mass (it is unbalanced).
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Carbon (C), Hydrogen (H), Oxygen (O)