Question

in the reaction: c₄h₆o₄ + fad → c₄h₄o₄ + fadh₂, what type of reaction took place to remove the protons from c₄h₆o₄? multiple choice decarboxylation reduction dehydrogenation oxidation

Explanation:

Dehydrogenation is the removal of hydrogen (including protons) from a molecule. In the given reaction, protons along with electrons are removed from $C_4H_6O_4$ and transferred to FAD to form $FADH_2$. Decarboxylation involves removal of a carboxyl group as $CO_2$. Reduction is gain of electrons (or hydrogen). Oxidation is loss of electrons (or hydrogen), but dehydrogenation specifically refers to removal of hydrogen.

Answer:

C. Dehydrogenation