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in the reaction of methane combustion, the balanced equation produces t…

Question

in the reaction of methane combustion, the balanced equation produces two molecules of carbon dioxide and two molecules of

Explanation:

Step1: Recall methane combustion reaction

Methane ($CH_4$) burns in oxygen ($O_2$) to produce carbon - dioxide ($CO_2$) and water ($H_2O$). The general un - balanced equation is $CH_4 + O_2
ightarrow CO_2+H_2O$.

Step2: Balance the equation

For the given situation where 2 moles of $CO_2$ are produced, since there is 1 carbon atom in $CH_4$, we need 2 moles of $CH_4$. Then, for hydrogen, 2 moles of $CH_4$ have 8 moles of hydrogen atoms. So, we get 4 moles of $H_2O$ to balance hydrogen. And for oxygen, 2 moles of $CO_2$ have 4 moles of oxygen atoms and 4 moles of $H_2O$ have 4 moles of oxygen atoms, so we need 4 moles of $O_2$. The balanced equation is $2CH_4 + 4O_2
ightarrow2CO_2 + 4H_2O$.

Answer:

Water