Question

ron is trying to work on his group potion project. in the version of advanced potion making he is given, the temperature listed for the potion is 485.05 k. help ron convert this to celsius to make sure he does not ruin the potion.
841.09 c
333.30 c
758.2 c
905.09 c
correct answer not provided
211.90 c
567.94 c
clear my selection
multiple answer 10 points
harry potter is touring macusa and begins to feel ill. madame pomfreys cousin ms. pomfrey works there and tells harry his temperature is 39.1°c. identify if harry is running a fever and what is their temperature in °f?
yes the harry is running a fever.
no the harry is not running a fever
375.53°f
102.38°f
21.3°f
102.4°f
correct temperature answer not provided
multiple choice 10 points
carry out the following calculation and report the answer using the proper number of significant figures: 8.32 x 10^(-4)/2.695 x 10^12
2.242 x 10^10

Explanation:

Step 1: Convert Kelvin to Celsius for Ron's potion

The formula to convert Kelvin (K) to Celsius (°C) is $T_{C}=T_{K}- 273.15$. Given $T_{K} = 485.05$ K, then $T_{C}=485.05 - 273.15=211.90$ °C.

Step 2: Determine if Harry has a fever and convert his temperature to Fahrenheit

Normal body - temperature is around 37 °C. Since Harry's temperature is 39.1 °C, he is running a fever. The formula to convert Celsius to Fahrenheit is $T_{F}=\frac{9}{5}T_{C}+32$. Substitute $T_{C}=39.1$ °C into the formula: $T_{F}=\frac{9}{5}\times39.1 + 32=70.38+32 = 102.38$ °F.

Step 3: Calculate the scientific - notation problem

When dividing numbers in scientific notation $\frac{a\times10^{m}}{b\times10^{n}}=\frac{a}{b}\times10^{m - n}$. For $\frac{8.32\times10^{-4}}{2.695\times10^{12}}$, $\frac{8.32}{2.695}\approx3.09$ and $10^{-4-12}=10^{-16}$. So the result is $3.09\times10^{-16}$.

Answer:

For the first question: 211.90 °C
For the second question: Yes the Harry is running a fever, 102.38°F
For the third question: The correct answer is not provided in the options (should be $3.09\times10^{-16}$)