Question

sch4u
alcohols, ethers, aldehydes, ketones, carboxylic acids, est
part a: draw the structure for the following organic molecules:

1. 2 - chloro - 2 - iodo - 3 - ethylhexanoic acid
2. 2 - ethylbutylbenzoate

Explanation:

Step1: Analyze the parent - chain and functional group

The parent - chain for 2 - chloro - 2 - iodo - 3 - ethylhexanoic acid is hexanoic acid, which has a 6 - carbon chain with a carboxylic acid group ($-COOH$) at one end.

Step2: Add substituents

There is a chloro ($-Cl$) and an iodo ($-I$) group at the 2 - position and an ethyl group ($-CH_2CH_3$) at the 3 - position. The structure is $CH_3CH_2CH(CH_2CH_3)C(Cl)(I)CH_2COOH$.

For 2 - ethylbutylbenzoate:

Step1: Identify the components

Benzoate indicates a benzene ring with a $-COO-$ group. The alcohol part of the ester is 2 - ethylbutyl. The butyl chain has 4 carbons, and there is an ethyl group at the 2 - position.

Step2: Draw the structure

The structure is $C_6H_5COOCH_2CH(CH_2CH_3)CH_2CH_3$.

Answer:

1. Structure of 2 - chloro - 2 - iodo - 3 - ethylhexanoic acid: $CH_3CH_2CH(CH_2CH_3)C(Cl)(I)CH_2COOH$
2. Structure of 2 - ethylbutylbenzoate: $C_6H_5COOCH_2CH(CH_2CH_3)CH_2CH_3$