QUESTION IMAGE
Question
section 2 review nses ps 1a section vocabulary boyle’s law the law that states that the volume of a gas is inversely proportional to the pressure of a gas when temperature is constant charles’s law the law that states that the volume of a gas is directly proportional to the temperature of a gas when pressure is constant pressure the amount of force exerted per unit area of a surface temperature a measure of how hot (or cold) something is; specifically, a measure of the average kinetic energy of the particles in an object volume a measure of the size of a body or region in three - dimensional space 1. identify name the three factors that affect how a gas behaves. 2. describe what happens to the temperature and volume of a balloon if it is taken outside on a cold winter day? 3. calculate you have three liters of gas at a certain kelvin temperature and a certain pressure. the kelvin temperature triples and the pressure stays the same. what is the gas volume? explain your answer.
- The vocabulary section lists the key factors that influence gas behavior, which are the three defined properties related to gas laws.
- This scenario follows Charles's Law, which describes the direct relationship between gas temperature and volume at constant pressure.
- This calculation uses Charles's Law, which states that at constant pressure, the volume of a gas is directly proportional to its Kelvin temperature.
Step1: State Charles's Law
$\frac{V_1}{T_1} = \frac{V_2}{T_2}$ where $V_1=3\ \text{L}$, $T_2=3T_1$
Step2: Solve for $V_2$
$V_2 = V_1 \times \frac{T_2}{T_1}$
Step3: Substitute values
$V_2 = 3\ \text{L} \times \frac{3T_1}{T_1} = 9\ \text{L}$
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
- The three factors are pressure, temperature, and volume.
- When taken outside on a cold winter day, the temperature of the gas inside the balloon decreases, and following Charles's Law (constant atmospheric pressure), the volume of the balloon will shrink (decrease).
3.