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section 2 review nses ps 1a section vocabulary boyle’s law the law that…

Question

section 2 review nses ps 1a section vocabulary boyle’s law the law that states that the volume of a gas is inversely proportional to the pressure of a gas when temperature is constant charles’s law the law that states that the volume of a gas is directly proportional to the temperature of a gas when pressure is constant pressure the amount of force exerted per unit area of a surface temperature a measure of how hot (or cold) something is; specifically, a measure of the average kinetic energy of the particles in an object volume a measure of the size of a body or region in three - dimensional space 1. identify name the three factors that affect how a gas behaves. 2. describe what happens to the temperature and volume of a balloon if it is taken outside on a cold winter day? 3. calculate you have three liters of gas at a certain kelvin temperature and a certain pressure. the kelvin temperature triples and the pressure stays the same. what is the gas volume? explain your answer.

Explanation:

Brief Explanations
  1. The vocabulary section lists the key factors that influence gas behavior, which are the three defined properties related to gas laws.
  2. This scenario follows Charles's Law, which describes the direct relationship between gas temperature and volume at constant pressure.
  3. This calculation uses Charles's Law, which states that at constant pressure, the volume of a gas is directly proportional to its Kelvin temperature.

Step1: State Charles's Law

$\frac{V_1}{T_1} = \frac{V_2}{T_2}$ where $V_1=3\ \text{L}$, $T_2=3T_1$

Step2: Solve for $V_2$

$V_2 = V_1 \times \frac{T_2}{T_1}$

Step3: Substitute values

$V_2 = 3\ \text{L} \times \frac{3T_1}{T_1} = 9\ \text{L}$

Answer:

  1. The three factors are pressure, temperature, and volume.
  2. When taken outside on a cold winter day, the temperature of the gas inside the balloon decreases, and following Charles's Law (constant atmospheric pressure), the volume of the balloon will shrink (decrease).

3.