QUESTION IMAGE
Question
section b: you may draw arrows to help you if you want but it is not required. write the names of the elements in the order they appear in the formula from left to right. if the element appears more than once, only write it once, then add its atoms together.
- 3na₂so₄
of molecules
of elements
name of element
of atoms
total # of atoms
the #3 is a
(coefficient or subscript)
- 2znso₄
of molecules
of elements
name of element
of atoms
total # of atoms
the #4 is a
(coefficient or subscript)
- k₂co₃
of molecules
of elements
name of element
of atoms
total # of atoms
the #3 is a
(coefficient or subscript)
- ba₃(po₄)₂
of molecules
of elements
name of element
of atoms
total # of atoms
the #3 is a
(coefficient or subscript)
- na₂cro₄
of molecules
of elements
name of element
of atoms
total # of atoms
the #4 is a
(coefficient or subscript)
- 4al₂(co₃)₃
of molecules
of elements
name of element
of atoms
total # of atoms
the assumed 1 is a
(coefficient or subscript)
Step1: Analyze 3Na₂SO₄
- # of molecules: 3 (the coefficient in front of the formula).
- # of elements: 3 (sodium - Na, sulfur - S, oxygen - O).
- Names of elements: Sodium, Sulfur, Oxygen.
- # of atoms: Na: 2×3 = 6, S: 1×3 = 3, O: 4×3 = 12. Total # of atoms: 6 + 3+12 = 21. The 3 is a coefficient.
Step2: Analyze 2ZnSO₄
- # of molecules: 2.
- # of elements: 3 (zinc - Zn, sulfur - S, oxygen - O).
- Names of elements: Zinc, Sulfur, Oxygen.
- # of atoms: Zn: 1×2 = 2, S: 1×2 = 2, O: 4×2 = 8. Total # of atoms: 2 + 2+8 = 12. The 2 is a coefficient.
Step3: Analyze K₂CO₃
- # of molecules: 1 (assumed when no coefficient is written).
- # of elements: 3 (potassium - K, carbon - C, oxygen - O).
- Names of elements: Potassium, Carbon, Oxygen.
- # of atoms: K: 2, C: 1, O: 3. Total # of atoms: 2 + 1+3 = 6. The 3 is a sub - script.
Step4: Analyze Ba₃(PO₄)₂
- # of molecules: 1.
- # of elements: 3 (barium - Ba, phosphorus - P, oxygen - O).
- Names of elements: Barium, Phosphorus, Oxygen.
- # of atoms: Ba: 3, P: 1×2 = 2, O: 4×2 = 8. Total # of atoms: 3+2 + 8 = 13. The 3 is a sub - script.
Step5: Analyze Na₂CrO₄
- # of molecules: 1.
- # of elements: 3 (sodium - Na, chromium - Cr, oxygen - O).
- Names of elements: Sodium, Chromium, Oxygen.
- # of atoms: Na: 2, Cr: 1, O: 4. Total # of atoms: 2 + 1+4 = 7. The 4 is a sub - script.
Step6: Analyze 4Al₂(CO₃)₃
- # of molecules: 4.
- # of elements: 3 (aluminum - Al, carbon - C, oxygen - O).
- Names of elements: Aluminum, Carbon, Oxygen.
- # of atoms: Al: 2×4 = 8, C: 1×3×4 = 12, O: 3×3×4 = 36. Total # of atoms: 8+12 + 36 = 56. The 1 (assumed in CO₃) is a sub - script.
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| Chemical Formula | # of Molecules | # of Elements | Names of Elements | # of Atoms | Total # of Atoms | Coefficient/Sub - script |
|---|---|---|---|---|---|---|
| 2ZnSO₄ | 2 | 3 | Zinc, Sulfur, Oxygen | Zn: 2, S: 2, O: 8 | 12 | 2 is a coefficient |
| K₂CO₃ | 1 | 3 | Potassium, Carbon, Oxygen | K: 2, C: 1, O: 3 | 6 | 3 is a sub - script |
| Ba₃(PO₄)₂ | 1 | 3 | Barium, Phosphorus, Oxygen | Ba: 3, P: 2, O: 8 | 13 | 3 is a sub - script |
| Na₂CrO₄ | 1 | 3 | Sodium, Chromium, Oxygen | Na: 2, Cr: 1, O: 4 | 7 | 4 is a sub - script |
| 4Al₂(CO₃)₃ | 4 | 3 | Aluminum, Carbon, Oxygen | Al: 8, C: 12, O: 36 | 56 | 1 (in CO₃) is a sub - script |