Question

select the correct answer. how many moles are contained in $3.131 \times 10^{24}$ particles? \\(\bigcirc\\) a. \\(5.199\\) mol \\(\bigcirc\\) b. \\(18.85\\) mol \\(\bigcirc\\) c. \\(0.5199 \times 10^{23}\\) mol \\(\bigcirc\\) d. \\(1.885 \times 10^{47}\\) mol

Explanation:

Step1: Recall Avogadro's number

1 mole = $6.022 \times 10^{23}$ particles

Step2: Calculate moles from particles

Moles = $\frac{\text{Number of particles}}{\text{Avogadro's number}}$
$\text{Moles} = \frac{3.131 \times 10^{24}}{6.022 \times 10^{23}}$

Step3: Compute the value

$\text{Moles} = \frac{3.131}{6.022} \times 10^{24-23} \approx 0.5199 \times 10^1 = 5.199$

Answer:

A. 5.199 mol