Question

select the correct answer. waters heat of vaporization is 2,257 joules/gram. how much energy is released when 11.2 grams of water vapor condenses into liquid?
a. 202 j
b. 2,246 j
c. 3,840 j
d. 9,950 j
e. 25,300 j

Explanation:

Step1: Identify the formula

The energy released $Q$ when a substance changes phase is given by $Q = m\times\Delta H_{vap}$, where $m$ is the mass and $\Delta H_{vap}$ is the heat of vaporization.

Step2: Substitute values

Here, $m = 11.2$ g and $\Delta H_{vap}=2257$ J/g. So $Q=11.2\times2257$.

Step3: Calculate the result

$Q = 11.2\times2257=25278.4\approx25300$ J.

Answer:

E. 25,300 J