Question

1. sep calculate the percent abundance of each isotope: divide the number of particles of each isotope by the total number of particles, and multiply the result by 100.

• limium 47.951÷100 = 0.47
• kidnium 22.35÷100 = 0.35
• peaium 14.150÷100 = 0.14
• navium 13.50÷100 = 0.13

1. sep use math the atomic mass of bg is a weighted average of the masses of the isotopes. the weighting factors are their relative abundances. use the following equation to calculate the “atomic mass” of bg. hint: divide the percent abundance of each isotope by 100 to obtain its relative abundance.

relative abundance = percent abundance/100
o limium
relative abundance:
o kidnium
relative abundance:
o peaium
relative abundance:
o navium
relative abundance:

Explanation:

Step1: Recall relative - abundance formula

Relative abundance = Percent abundance/100

Step2: Calculate relative abundance of Limium

Given percent abundance of Limium is 47.951. So relative abundance = $\frac{47.951}{100}=0.47951$

Step3: Calculate relative abundance of Kidnium

Given percent abundance of Kidnium is 22.35. So relative abundance = $\frac{22.35}{100}=0.2235$

Step4: Calculate relative abundance of Peaium

Given percent abundance of Peaium is 14.150. So relative abundance = $\frac{14.150}{100}=0.1415$

Step5: Calculate relative abundance of Navium

Given percent abundance of Navium is 13.50. So relative abundance = $\frac{13.50}{100}=0.135$

Answer:

Limium Relative Abundance: 0.47951
Kidnium Relative Abundance: 0.2235
Peaium Relative Abundance: 0.1415
Navium Relative Abundance: 0.135