Question

slide 12: practice: carbon - 13
atomic number = 6

of protons = 6

of neutrons = 13 - 6 = 7

of electrons = 6

mass number = 13
symbol notation = c

slide 13: practice: nitrogen - 15
atomic number = 7

of protons = 7

of neutrons = 15 - 7 = 8

of electrons = 7

mass number = 15
symbol notation = $_{7}^{15}n$

slide 14: practice: $_{8}^{18}o$
atomic number =

of protons =

of neutrons =

of electrons =

mass number = 18
name notation = oxygen

slide 15: practice: $_{35}^{82}br$
atomic number =

of protons =

of neutrons =

of electrons =

mass number = 82
name notation =

slide 16: announcements
next lecture - come ready to take notes
next lab - bring your lab gear
start packing a calculator in your bag everyday!

Explanation:

Step1: Recall atomic - number concept

Atomic number = number of protons. For $^{18}_8O$, atomic number is 8, so number of protons = 8.

Step2: Calculate number of neutrons

Mass number = number of protons + number of neutrons. Given mass number = 18 and number of protons = 8, number of neutrons = 18 - 8 = 10.

Step3: Determine number of electrons

In a neutral atom, number of electrons = number of protons. So number of electrons = 8.

For $^{82}_{35}Br$:

Step1: Identify atomic number

Atomic number = 35, so number of protons = 35.

Step2: Calculate number of neutrons

Mass number = 82, number of neutrons = 82 - 35 = 47.

Step3: Determine number of electrons

Number of electrons = number of protons = 35.

Step4: Name notation

Name notation is Bromine.

Answer:

For $^{18}_8O$: Atomic Number = 8, # of Protons = 8, # of Neutrons = 10, # of Electrons = 8, Mass Number = 18, Name Notation = Oxygen
For $^{82}_{35}Br$: Atomic Number = 35, # of Protons = 35, # of Neutrons = 47, # of Electrons = 35, Mass Number = 82, Name Notation = Bromine