Question

solid magnesium hydroxide decomposes into solid magnesium oxide and gaseous water. write a balanced chemical equation for this reaction.

Explanation:

Step1: Write the reactant and products

The reactant is magnesium hydroxide ($Mg(OH)_2$) and the products are magnesium oxide ($MgO$) and water ($H_2O$). So the un - balanced equation is $Mg(OH)_2
ightarrow MgO + H_2O$.

Step2: Check the atom balance

On the left - hand side, we have 1 Mg, 2 O, and 2 H from $Mg(OH)_2$. On the right - hand side, we have 1 Mg, 2 O (1 in $MgO$ and 1 in $H_2O$), and 2 H. The equation is already balanced.

Answer:

$Mg(OH)_2(s)
ightarrow MgO(s)+H_2O(g)$