Question

1. the solubility of oxygen gas is 0.007 g/100 ml at stp conditions. how much oxygen gas is dissolved in the following situations? a. 0.007 g of o₂(g) is bubbled in 100 ml of water b. 0.008 g of o₂(g) is bubbled in 100 ml of water c. 0.050 g of o₂(g) is bubbled in 300 ml of water

Explanation:

Step1: Recall solubility concept

The solubility of oxygen is 0.007 g/100 mL at STP. This means the maximum amount of oxygen that can dissolve in 100 mL of water is 0.007 g.

Step2: Solve part a

Since the amount of oxygen bubbled (0.007 g) is equal to the solubility limit for 100 mL of water, the amount dissolved is 0.007 g.

Step3: Solve part b

The solubility limit for 100 mL of water is 0.007 g. When 0.008 g is bubbled, only 0.007 g will dissolve (reaching the saturation point).

Step4: Solve part c

First, find the solubility for 300 mL. Since solubility is 0.007 g/100 mL, for 300 mL it is $0.007\times\frac{300}{100}= 0.021$ g. The amount of oxygen bubbled is 0.050 g which is more than the solubility limit for 300 mL. So, 0.021 g will dissolve.

Answer:

a. 0.007 g
b. 0.007 g
c. 0.021 g