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solve by any method: ( x^2 - 8x = -15 ) ( x = 3 ) or ( x = -5 ) ( x = 3…

Question

solve by any method: ( x^2 - 8x = -15 )
( x = 3 ) or ( x = -5 )
( x = 3 ) or ( x = 5 )
( x = -3 ) or ( x = 5 )
( x = -3 ) or ( x = -5 )

Explanation:

Step1: Rearrange to standard form

$x^2 - 8x + 15 = 0$

Step2: Factor the quadratic

$(x-3)(x-5) = 0$

Step3: Solve for x

Set $x-3=0 \implies x=3$; Set $x-5=0 \implies x=5$

Answer:

x = 3 or x = 5