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Question
solve by any method: ( x^2 - 8x = -15 )
( x = 3 ) or ( x = -5 )
( x = 3 ) or ( x = 5 )
( x = -3 ) or ( x = 5 )
( x = -3 ) or ( x = -5 )
Step1: Rearrange to standard form
$x^2 - 8x + 15 = 0$
Step2: Factor the quadratic
$(x-3)(x-5) = 0$
Step3: Solve for x
Set $x-3=0 \implies x=3$; Set $x-5=0 \implies x=5$
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x = 3 or x = 5