Question

temperature (°c) 0 10 20 30 40 50 60 70 80 90 100 57°c 33°c 75°c 94°c clear selection lead has a density of 11.3 g/ml and a mass of 282.5 g. what is its volume? 1 point 2.5 ml 25 ml 250 ml 2500 ml

Explanation:

For the temperature - related question (assuming it's about solubility or gas behavior, but here we focus on the lead volume question):

Step1: Recall the density formula

The formula for density is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass, and $V$ is volume. We need to solve for $V$, so we can rearrange the formula to $V = \frac{m}{
ho}$.

Step2: Substitute the given values

We know that the mass $m = 282.5\space g$ and the density $
ho=11.3\space g/mL$. Substituting these values into the formula for $V$, we get $V=\frac{282.5}{11.3}$.

Step3: Perform the division

Calculating $\frac{282.5}{11.3}$, we find that $282.5\div11.3 = 25$. So the volume $V = 25\space mL$.

From the given options and the marked selection (the red - circled option), the answer is $57^{\circ}C$.

Answer:

25 mL (corresponding to the option "25 mL")

For the temperature - related multiple - choice question (if we assume it's about the boiling point or some property of $SO_2$ from the graph, but since the graph is partially visible, if we consider the marked option and the context, the selected option is $57^{\circ}C$):