Question

these exercises require computations with bilateral tolerances of mating parts with interference fits. given dimensions a and b, compute the missing values in the tables. refer to figure 7 - 21 to determine the missing values in figure 7 - 22. figure 7 - 21 dia a ± 0.03 mm dia b ± 0.03 mm figure 7 - 22 basic dimension (mm) maximum diameter (mm) minimum diameter (mm) maximum clearance (mm) minimum clearance (mm) 59. dia a 9.94 dia b 9.85

Explanation:

Step1: Find the basic dimension of DIA A

Since the maximum diameter of DIA A is 9.94 mm and the tolerance is ±0.03 mm, we use the formula for maximum dimension $D_{max}=D_{basic}+tolerance$. Let the basic dimension be $x$, then $x + 0.03=9.94$. Solving for $x$, we get $x=9.94 - 0.03=9.91$ mm.

Step2: Find the minimum diameter of DIA A

Using the formula $D_{min}=D_{basic}-tolerance$, substituting $D_{basic}=9.91$ mm and tolerance = 0.03 mm, we have $D_{min}=9.91- 0.03 = 9.88$ mm.

Step3: Find the basic dimension of DIA B

Since the maximum diameter of DIA B is 9.85 mm and the tolerance is ±0.03 mm, using $D_{max}=D_{basic}+tolerance$. Let the basic dimension be $y$, then $y + 0.03=9.85$. Solving for $y$, we get $y=9.85 - 0.03=9.82$ mm.

Step4: Find the minimum diameter of DIA B

Using the formula $D_{min}=D_{basic}-tolerance$, substituting $D_{basic}=9.82$ mm and tolerance = 0.03 mm, we have $D_{min}=9.82- 0.03 = 9.79$ mm.

Step5: Calculate maximum clearance

Maximum clearance occurs when $D_{A(min)}-D_{B(max)}$. So, maximum clearance $=9.88 - 9.85=0.03$ mm.

Step6: Calculate minimum clearance

Minimum clearance occurs when $D_{A(max)}-D_{B(min)}$. So, minimum clearance $=9.94 - 9.79 = 0.15$ mm.

Answer:

	Basic Dimension (mm)	Maximum Diameter (mm)	Minimum Diameter (mm)	Maximum Clearance (mm)	Minimum Clearance (mm)
DIA B	9.82	9.85	9.79	0.03	0.15